JEE Main 2021 (26 Aug, Shift 2) Chemistry Q44: reaction…

Question

[reaction scheme] drawn structure --($\mathrm{Br_2}$ / $\mathrm{AlBr_3}$ $(\mathrm{C_2H_5})_2\mathrm{O}$)--> ‘A’ (Major Product)
Consider the given reaction, the Product $\mathbf{A}$ is :

Accepted Answer

Option 1: [figure: benzene ring bearing a C=O group, the carbonyl carbon continuing into a four-carbon zigzag chain; a Br is attached to the ring at the ring position two bonds away from the carbonyl-bearing carbon (meta-type position as drawn, below the ring)]

Answer

[figure: benzene ring bearing a C=O group, the carbonyl carbon continuing into a four-carbon zigzag chain; a Br is attached to the ring at the ring position two bonds away from the carbonyl-bearing carbon (meta-type position as drawn, below the ring)]

Answer

[figure: benzene ring bearing a C=O group, the carbonyl carbon continuing into a four-carbon zigzag chain; Br is attached to the last (terminal) carbon of the chain]

Answer

[figure: benzene ring bearing a C=O group, the carbonyl carbon continuing into a four-carbon zigzag chain; Br is attached to the third carbon after the carbonyl carbon, the carbon next to the terminal carbon]

Answer

[figure: benzene ring bearing a C=O group, the carbonyl carbon continuing into a four-carbon zigzag chain; Br is attached to the ring at the position opposite (para, lower left) to the carbonyl-bearing carbon]

JEE Main 26 August 2021, Shift 2, Chemistry Q44

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