JEE Main 2021 · PhysicsNumerical answerNumerical valueEasyCalculation

JEE Main 26 August 2021, Shift 2, Physics Q28

Question 28 of 90 in this shift, Physics question 28 of 30, Section B.

A circular coil of radius 8.0 cm and 20 turns is rotated about its vertical diameter with an angular speed of 50 rad s

^{-1}

in a uniform horizontal magnetic field of

3.0\times10^{-2}

T. The maximum emf induced the coil will be __________

\times10^{-2}

volt (rounded off to the nearest integer).

Official answer

NTA final key.

Chapter: Electromagnetic Induction
Topic: Faraday's Law
Idea tested: AC Generator Principle

Same idea in other shifts

Asked 5× in all

1 Feb 2024, Shift 2 · Q58A coil of 200 turns and area $0.20\ \mathrm{m^2}$ is rotated at half a revolution per second and is placed in uniform magnetic field of…EasyNumerical value
24 Jun 2022, Shift 2 · Q58A circular coil of 1000 turns each with area 1m $^2$ is rotated about its vertical diameter at the rate of one revolution per second in a…EasyNumerical value
2 Sep 2020, Shift 1 · Q24A circular coil of radius 10 cm is placed in a uniform magnetic field of $3.0\times10^{-5}$ T with its plane perpendicular to the field…MediumNumerical value
3 Sep 2020, Shift 1 · Q14An elliptical loop having resistance R, of semi major axis a, and semi minor axis b is placed in a magnetic field as shown in the figure.…MediumSingle correctHas a figure

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.