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Saturday, 31 October

JEE Main 2021 · PhysicsNumerical answerNumerical valueMediumMulti-step

JEE Main 26 August 2021, Shift 2, Physics Q21

Question 21 of 90 in this shift, Physics question 21 of 30, Section B.

The coefficient of static friction between two blocks is 0.5 and the table is smooth. The maximum horizontal force that can be applied to move the blocks together is __________ N. (take g=10 ms−2\mathrm{g}=10\ \mathrm{ms^{-2}})

The figure, in words

A 1 kg block rests on top of a 2 kg block, which sits on a table (hatched ground, arrow labelled 'Table'); μ = 0.5 is labelled beside the blocks; a horizontal force F acts rightwards on the 2 kg block.

Official answer

15

NTA final key.

Same idea in other shifts

Asked 3× in all
  1. 27 Jun 2022, Shift 1 · Q34A system of two blocks of masses m=2m=2 kg and M=8M=8 kg is placed on a smooth table as shown in figure. The coefficient of static friction…MediumSingle correctHas a figure
  2. 17 Mar 2021, Shift 1 · Q30Two blocks (m = 0.5 kg and M = 4.5 kg) are arranged on a horizontal frictionless table as shown in figure. The coefficient of static…MediumNumerical valueHas a figure

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. This question needs a figure we do not reproduce; it is described in words above. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.