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Saturday, 31 October

JEE Main 2021 · PhysicsMultiple choiceSingle correctMediumMulti-step

JEE Main 26 August 2021, Shift 2, Physics Q11

Question 11 of 90 in this shift, Physics question 11 of 30, Section A.

A light beam is described by E=800 sin⁡ω(t−xc)\mathrm{E}=800\,\sin\omega\left(\mathrm{t}-\frac{x}{\mathrm{c}}\right). An electron is allowed to move normal to the propagation of light beam with a speed of 3×107 ms−13\times10^{7}\ \mathrm{ms^{-1}}. What is the maximum magnetic force exerted on the electron ?
  1. (1)1.28×10−181.28\times10^{-18} N
  2. (2)12.8×10−1812.8\times10^{-18} NOfficial answer
  3. (3)12.8×10−1712.8\times10^{-17} N
  4. (4)1.28×10−211.28\times10^{-21} N

Official answer

Option 2

NTA final key.

Topic
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Idea tested
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Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.