JEE Main 2021 · ChemistryMultiple choiceOtherMediumApplication
JEE Main 26 August 2021, Shift 1, Chemistry Q45
Question 45 of 90 in this shift, Chemistry question 15 of 30, Section A.
The major products formed in the following reaction sequence A and B are :
[figure: hexagonal ring joined to a carbonyl carbon (C=O) which carries ; arrow with above and KOH below, giving A + B]
The figure, in words
Reactant: hexagonal ring (hexagon with inner circle) attached to a C(=O) carbon bearing CH3. Reagents on the arrow: Br2 above, KOH below. Option 2 drawings: Br labels on two ring vertices (upper-left and lower-left) in A and HO labels on two ring vertices (upper-left and lower-left) in B, with C(=O)-CH3 on the right vertex. Option 3 drawings: one Br label at the lower-left ring vertex in both A and B.- (1)A = [figure: hexagonal ring bonded to C(=O)OK], B = Official answer
- (2)A = [figure: hexagonal ring bearing Br at two ring positions and the group C(=O)-CH3], B = [figure: hexagonal ring bearing HO at two ring positions and the group C(=O)-CH3]
- (3)A = [figure: hexagonal ring bearing Br on the ring and the group C(=O)-CH2-Br], B = [figure: hexagonal ring bearing Br on the ring and the group C(=O)-CH2-OH]
- (4)A = [figure: hexagonal ring bonded to C(=O)-CBr3], B = [figure: hexagonal ring bonded to CHO]
Official answer
Option 1
NTA final key.
- Topic
- Aldol and Cannizzaro
- Idea tested
- Haloform Interference with Aldol