JEE Main 2021 · PhysicsMultiple choiceSingle correctEasyCalculation

JEE Main 26 August 2021, Shift 1, Physics Q4

Question 4 of 90 in this shift, Physics question 4 of 30, Section A.

An electric appliance supplies 6000 J/min heat to the system. If the system delivers a power of 90 W. How long it would take to increase the internal energy by

2.5\times10^{3}

J ?

(1) $2.5\times10^{1}$ s
(2) $2.5\times10^{2}$ sOfficial answer
(3) $2.4\times10^{3}$ s
(4) $4.1\times10^{1}$ s

Official answer

Option 2

NTA final key.

Chapter: Thermodynamics
Topic: First Law of Thermodynamics
Idea tested: First Law Energy Balance

Same idea in other shifts

Asked 3× in all

6 Apr 2024, Shift 2 · Q39A total of 48 J heat is given to one mole of helium kept in a cylinder. The temperature of helium increases by $2^\circ\mathrm{C}$ . The…EasySingle correct
6 Apr 2023, Shift 1 · Q44A source supplies heat to a system at the rate of 1000 W. If the system performs work at a rate of 200 W. The rate at which internal…EasySingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.