JEE Main 2021 (4 Aug, Shift 2) Maths Q74: Normals to Conics

Question

Let the normal at any point of hyperbola $\frac{x^2}{a^2}-\frac{y^2}{b^2}=1$ intersect the coordinate axes at points P and Q. Then the locus of the mid-point of PQ is :

Accepted Answer

Option 4: $4\left(a^2x^2-b^2y^2\right)=\left(a^2+b^2\right)$

Answer

$2\left(b^2x^2+a^2y^2\right)=a^2+b^2$

Answer

$2\left(b^2x^2-a^2y^2\right)=a^2+b^2$

Answer

$4\left(a^2x^2+b^2y^2\right)=\left(a^2+b^2\right)^2$

Answer

$4\left(a^2x^2-b^2y^2\right)=\left(a^2+b^2\right)$

JEE Main 4 August 2021, Shift 2, Maths Q74

Same idea in other shifts