JEE Main 2021 · PhysicsNumerical answerNumerical valueMediumCalculation

JEE Main 4 August 2021, Shift 2, Physics Q26

Question 26 of 90 in this shift, Physics question 26 of 30, Section B.

Employing a resistance of

8\Omega

, a capacitor is charged through a battery of 12V. In

2\mu\mathrm{s}

time, the potential difference across the capacitor is found to be 6V. The storage capacity of the capacitor is

\frac{x}{100}\mu\mathrm{F}

. Then the value of x is _____. (

\ln2=0.69

)

Official answer

NTA final key.

Chapter: Electrostatic Potential and Capacitance
Topic: RC Circuits
Idea tested: Charging Equation Mastery

Same topic in other shifts

All RC Circuits questions

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Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.