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Saturday, 31 October

JEE Main 2021 · PhysicsNumerical answerNumerical valueMediumCalculation

JEE Main 4 August 2021, Shift 2, Physics Q24

Question 24 of 90 in this shift, Physics question 24 of 30, Section B.

A particle of mass 1 kg is projected at t = 0 from a point ‘O’ on the ground with a speed ‘u’ at an angle 45°45° to the horizontal. The magnitude of angular momentum of the particle about ‘O’ at time ug\frac{u}{g} is given by 7u3ag\frac{7u^3}{ag}. Then the value of a is _________. (Take 12=0.7\frac{1}{\sqrt{2}}=0.7 and g=10 m/s2g=10\,m/s^2)

The figure, in words

Axes: y axis (vertical, arrow up) and x axis (horizontal, arrow right) meeting at O. A solid arrow from O points up and to the right, with the angle between it and the x axis marked 45°. A dashed arc from O rises and comes back down to the x axis further right.

Official answer

20

NTA final key.