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Saturday, 31 October

JEE Main 2021 · PhysicsMultiple choiceSingle correctEasyCalculation

JEE Main 4 August 2021, Shift 2, Physics Q1

Question 1 of 90 in this shift, Physics question 1 of 30, Section A.

A p-type semiconductor has accepter levels 60 meV above the valence band. What will be the maximum wavelength of em wave which can create a hole ? (Plank’s constant = 4.14×10−154.14 \times 10^{-15} eV-s, Speed of light in vacuum = 3×1083 \times 10^{8} ms−1^{-1})
  1. (1)20.7 μm20.7\ \mu\mathrm{m}Official answer
  2. (2)30.8 μm30.8\ \mu\mathrm{m}
  3. (3)40.9 μm40.9\ \mu\mathrm{m}
  4. (4)50.0 μm50.0\ \mu\mathrm{m}

Official answer

Option 1

NTA final key.

Chapter
Semiconductor Electronics: Materials, Devices and Simple Circuits
Topic
No close match in our taxonomy
Idea tested
No close match in our taxonomy

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.