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Saturday, 31 October

JEE Main 2021 · MathsMultiple choiceSingle correctEasyCalculation

JEE Main 3 August 2021, Shift 1, Maths Q77

Question 77 of 90 in this shift, Maths question 17 of 30, Section A.

If ∑i=116ai−6=8\sum_{i=1}^{16} a_i - 6 = 8 and ∑i=116ai−6 2=40\sum_{i=1}^{16} a_i - 6^{\,2} = 40, then the standard deviation of a1,a2,…,a16a_1, a_2, \ldots, a_{16} is
  1. (1)23\frac{2}{3}
  2. (2)32\frac{3}{2}Official answer
  3. (3)52\frac{5}{2}
  4. (4)25\frac{2}{5}

Official answer

Option 2

NTA final key.

Chapter
Statistics