JEE Main 2021 · PhysicsMultiple choiceDiagram basedMediumConceptual
JEE Main 3 August 2021, Shift 1, Physics Q13
Question 13 of 90 in this shift, Physics question 13 of 30, Section A.
A current I enters a circular coil of radius R, branches into two parts at A and then recombines at B (as shown in figure). The resultant magnetic field at the centre of the coil is -
The figure, in words
A circle with centre O (filled dot). A straight wire carrying current I enters from the left (horizontal arrow, labelled I) at point A on the left of the circle; a dashed horizontal line joins A to O. A second dashed line joins O to point B on the upper right of the circle, labelled R, with an angle of 120° marked at O between OA and OB (on the upper side). The upper arc from A to B carries I1 (arrow along the arc, labelled I1) and the lower arc from A round the bottom to B carries I2 (double arrowhead, labelled I2). At B the wire continues straight up and to the right with an arrow labelled I. The label 'I = I1+I2' is printed to the right of the circle.- (1)
- (2)
- (3)
- (4)ZeroOfficial answer
Official answer
Option 4
NTA final key.
- Chapter
- Moving Charges and Magnetism
- Topic
- Biot-Savart Law
- Idea tested
- Field at center of circular arc