JEE Main 2020 · ChemistryMultiple choiceSingle correctMediumMulti-step

JEE Main 6 September 2020, Shift 2, Chemistry Q41

Question 41 of 75 in this shift, Chemistry question 16 of 25.

A crystal is made up of metal ions 'M

_1

' and 'M

_2

' and oxide ions. Oxide ions form a ccp lattice structure. The cation 'M

_1

' occupies 50% of octahedral voids and the cation 'M

_2

' occupies 12.5% of tetrahedral voids of oxide lattice. The oxidation numbers of 'M

_1

' and 'M

_2

' are, respectively :

(1) $+2, +4$ Official answer
(2) $+4, +2$
(3) $+1, +3$
(4) $+3, +1$

Official answer

Option 1

NTA final key (Sep 2020).

Chapter: The Solid State
Topic: Crystal Lattices
Idea tested: Empirical Formula from Void Occupancy

Same idea in other shifts

Asked 4× in all

24 Jun 2022, Shift 1 · Q81Atoms of element X form hcp lattice and those of element Y occupy $\frac{2}{3}$ of its tetrahedral voids. The percentage of element X in…MediumNumerical value
26 Jun 2022, Shift 2 · Q82In a solid AB, A atoms are in ccp arrangement and B atoms occupy all the octahedral sites. If two atoms from the opposite faces are…MediumNumerical value
31 Aug 2021, Shift 2 · Q52The empirical formula for a compound with a cubic close packed arrangement of anions and with cations occupying all the octahedral sites…EasyNumerical value

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.