JEE Main 2020 · PhysicsMultiple choiceDiagram basedMediumDiagram reading
JEE Main 4 September 2020, Shift 1, Physics Q2
Question 2 of 75 in this shift, Physics question 2 of 25.
A Tennis ball is released from a height h and after freely falling on a wooden floor it rebounds and reaches height . The velocity versus height of the ball during its motion may be represented graphically by :
(graph are drawn schematically and on not to scale)
The figure, in words
Each option is a graph with vertical axis labelled v and horizontal axis labelled h(v), with points h/2 and h marked on the horizontal axis. Option 1: a curve with an arrow starts high on the v axis and descends (concave, flattening) to the point h/2 on the horizontal axis; a second curve with a downward-left arrow runs from the point h on the horizontal axis down to a point low on the v axis (below the origin). Option 2: same layout with straight line segments instead of curves (upper segment from the v axis down to h/2 with an arrow; lower segment from h down-left to the v axis below the origin with an arrow). Option 3: a quarter-circle-like arc with an arrow from the top of the v axis curving down to h/2, and a second arc from near h curving down and left to the v axis below the origin. Option 4: a small loop above the horizontal axis (arrow pointing right, from the origin to about h/2) joined to a larger loop below the axis (arrow pointing left) reaching out to about h.- (1)[figure: graph]
- (2)[figure: graph]
- (3)[figure: graph]Official answer
- (4)[figure: graph]
Official answer
Option 3
NTA final key (Sep 2020).
- Chapter
- Motion in a Straight Line
- Topic
- Kinematics in 1D
- Idea tested
- Free Fall Sign Conventions