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Saturday, 31 October

JEE Main 2020 · PhysicsMultiple choiceSingle correctEasyConceptual

JEE Main 4 September 2020, Shift 1, Physics Q1

Question 1 of 75 in this shift, Physics question 1 of 25.

Dimensional formula for thermal conductivity is (here K denotes the temperature) :
  1. (1)MLT−2K\mathrm{MLT^{-2}K}
  2. (2)MLT−3K−1\mathrm{MLT^{-3}K^{-1}}Official answer
  3. (3)MLT−3K\mathrm{MLT^{-3}K}
  4. (4)MLT−2K−2\mathrm{MLT^{-2}K^{-2}}

Official answer

Option 2

NTA final key (Sep 2020).

Chapter
Thermal Properties of Matter
Topic
No close match in our taxonomy
Idea tested
No close match in our taxonomy

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.