JEE Main 2020 · PhysicsMultiple choiceSingle correctMediumCalculation

JEE Main 3 September 2020, Shift 2, Physics Q7

Question 7 of 75 in this shift, Physics question 7 of 25.

A calorimeter of water equivalent 20 g contains 180 g of water at

25^\circ

C. 'm' grams of steam at

100^\circ

C is mixed in it till the temperature of the mixure is

31^\circ

C. The value of 'm' is close to (Latent heat of water

= 540

cal g

^{-1}

, specific heat of water

= 1

cal g

^{-1}

^\circ

^{-1}

)

(1)2Official answer
(2)2.6
(3)3.2
(4)4

Official answer

Option 1

NTA final key (Sep 2020).

Chapter: Thermal Properties of Matter
Topic: Calorimetry
Idea tested: Steam Injection Phase Dynamics

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Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.