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JEE Main 2020 · PhysicsMultiple choiceSingle correctMediumCalculation

JEE Main 3 September 2020, Shift 2, Physics Q6

Question 6 of 75 in this shift, Physics question 6 of 25.

A metallic sphere cools from

50^\circ

C to

40^\circ

C in 300 s. If atmospheric temperature around is

20^\circ

C, then the sphere's temperature after the next 5 minutes will be close to :

(1) $28^\circ$ C
(2) $31^\circ$ C
(3) $33^\circ$ COfficial answer
(4) $35^\circ$ C

Official answer

Option 3

NTA final key (Sep 2020).

Chapter: Thermal Properties of Matter
Topic: Thermal Radiation
Idea tested: Average Temperature Method for Newton's Law of Cooling

Same idea in other shifts

Asked 2× in all

12 Apr 2023, Shift 1 · Q37A body cools from $80^\circ$ C to $60^\circ$ C in 5 minutes. The temperature of the surrounding is $20^\circ$ C. The time it takes to cool…MediumSingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.