JEE Main 2020 · ChemistryMultiple choiceSingle correctMediumApplication
JEE Main 2 September 2020, Shift 2, Chemistry Q40
Question 40 of 75 in this shift, Chemistry question 15 of 25.
The major product of the following reaction is :
reactant (drawn structure) with the arrow labelled: conc. + conc.
The figure, in words
Reactant drawn: benzene ring (six-membered ring with alternating double bonds drawn); OH at the top vertex, CH3 at the upper-left vertex, NO2 at the lower-right vertex; no other substituents. Reagent over the arrow: conc. HNO3 + conc. H2SO4. Each option is a drawn ring structure with substituents at the vertices as described in the option text.- (1)[figure: benzene ring (six-membered ring with alternating double bonds drawn); OH at the top vertex, H3C at the upper-left vertex, NO2 at the lower-right vertex and NO2 at the bottom vertex; other vertices have no substituent drawn]Official answer
- (2)[figure: benzene ring; OH at the top vertex, H3C at the upper-left vertex, O2N at the lower-left vertex and NO2 at the lower-right vertex; other vertices have no substituent drawn]
- (3)[figure: benzene ring; OH at the top vertex, H3C at the upper-left vertex, NO2 at the upper-right vertex and NO2 at the lower-right vertex; other vertices have no substituent drawn]
- (4)[figure: benzene ring; OH at the top vertex, H3C at the upper-left vertex, NO2 at the upper-right vertex, NO2 at the lower-right vertex and NO2 at the bottom vertex; other vertices have no substituent drawn]
Official answer
Option 1
NTA final key (Sep 2020).
- Chapter
- Alcohols, Phenols and Ethers