JEE Main 2020 · ChemistryMultiple choiceDiagram basedMediumConceptual

JEE Main 2 September 2020, Shift 2, Chemistry Q39

Question 39 of 75 in this shift, Chemistry question 14 of 25.

Arrange the following labelled hydrogens in decreasing order of acidity :

The figure, in words

Drawn: a benzene ring (alternating double bonds drawn) fused to a six-membered ring drawn with single bonds. Substituents as drawn: NO2 on the aromatic carbon at the top next to the ring fusion; on the other ring, the top carbon bears a substituent printed 'C≡C–H' with the H circled and labelled subscript a; the lower carbon of that ring bears 'COO–H' with the H circled and labelled subscript b; the aromatic carbon at the bottom next to the ring fusion bears 'O–H' with the H circled and labelled subscript c; the aromatic carbon at the left bears 'O–H' drawn as 'd(H)–O' with the H circled and the letter d printed before it.

(1) $\mathrm{b} > \mathrm{c} > \mathrm{d} > \mathrm{a}$ Official answer
(2) $\mathrm{c} > \mathrm{b} > \mathrm{d} > \mathrm{a}$
(3) $\mathrm{b} > \mathrm{a} > \mathrm{c} > \mathrm{d}$
(4) $\mathrm{c} > \mathrm{b} > \mathrm{a} > \mathrm{d}$

Official answer

Option 1

NTA final key (Sep 2020).

Chapter: Organic Chemistry: Some Basic Principles and Techniques
Topic: Organic Acidity and Basicity
Idea tested: Carboxylic Acid Acidity

JEE Main 2 September 2020, Shift 2, Chemistry Q39

Same idea in other shifts