JEE Main 2020 · PhysicsNumerical answerNumerical valueMediumCalculation

JEE Main 2 September 2020, Shift 2, Physics Q23

Question 23 of 75 in this shift, Physics question 23 of 25.

A wire of density

9\times10^{-3}

kg cm

^{-3}

is stretched between two clamps 1 m apart. The resulting strain in the wire is

4.9\times10^{-4}

. The lowest frequency of the transverse vibrations in the wire is (Young’s modulus of wire Y=

9\times10^{10}

^{-2}

), (to the nearest integer), __________.

Official answer

35.00

NTA final key (Sep 2020).

Chapter: Waves
Topic: Waves on Strings
Idea tested: Wave Speed in Elastic Strings

Same topic in other shifts

All Waves on Strings questions

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Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.