JEE Main 2025 · PhysicsMultiple choiceSingle correctEasyApplication

JEE Main 8 April 2025, Shift 2, Physics Q34

Question 34 of 75 in this shift, Physics question 9 of 25, Section A.

Two strings with circular cross section and made of same material, are stretched to have same amount of tension. A transverse wave is then made to pass through both the strings. The velocity of the wave in the first string having the radius of cross section R is

v_1

, and that in the other string having radius of cross section R/2 is

v_2

. Then

\frac{v_2}{v_1} =

(1)4
(2)2Official answer
(3)8
(4) $\sqrt{2}$

Official answer

Option 2

NTA final key.

Chapter: Waves
Topic: Waves on Strings
Idea tested: Wave Speed on String

Same idea in other shifts

Asked 9× in all

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Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.