JEE Main 2020 (8 Jan, Shift 1) Physics Q4: Angular Momentum

Question

Consider a uniform rod of mass M = 4m and length $l$ pivoted about its centre. A mass m moving with velocity $v$ making angle $	heta = \frac{\pi}{4}$ to the rod's long axis collides with one end of the rod and sticks to it. The angular speed of the rod-mass system just after the collision is :

Accepted Answer

Option 3: $\frac{3\sqrt{2}}{7}\frac{v}{l}$

Answer

$\frac{3}{7}\frac{v}{l}$

Answer

$\frac{3}{7\sqrt{2}}\frac{v}{l}$

Answer

$\frac{3\sqrt{2}}{7}\frac{v}{l}$

Answer

$\frac{4}{7}\frac{v}{l}$

JEE Main 8 January 2020, Shift 1, Physics Q4

Same idea in other shifts