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JEE Main 8 January 2020, Shift 1, Physics Q21

Question 21 of 75 in this shift, Physics question 21 of 25, Section B.

A particle is moving along the

x

-axis with its coordinate with time 't' given by

x(t) = 10+8t-3t^2

. Another particle is moving along the

y

-axis with its coordinate as a function of time given by

y(t) = 5-8t^3

. At

t = 1

s, the speed of the second particle as measured in the frame of the first particle is given as

\sqrt{v}

. Then

v

(in m/s) is ______.

Official answer

580.00

NTA final key (Jan 2020).

Chapter: Motion in a Plane
Topic: Kinematics in 2D
Idea tested: Relative Velocity Vector Subtraction

Same topic in other shifts

All Kinematics in 2D questions

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Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.