JEE Main 2026 · ChemistryNumerical answerNumerical valueEasyCalculation

JEE Main 6 April 2026, Shift 2, Chemistry Q75

Question 75 of 75 in this shift, Chemistry question 25 of 25, Section B.

Decomposition of a hydrocarbon follows the equation

k=(5.5\times10^{11}\,\mathrm{s^{-1}})\,e^{\frac{-28000\,\mathrm{K}}{T}}

. The activation energy of reaction is __________ kJ mol

^{-1}

. (Nearest Integer) Given : R = 8.3 J K

^{-1}

mol

^{-1}

Official answer

232

NTA final key.

Chapter: Chemical Kinetics
Topic: Arrhenius Equation
Idea tested: Arrhenius Exponential Form

Same idea in other shifts

Asked 4× in all

30 Jun 2022, Shift 1 · Q84For the reaction P $\rightarrow$ B, the values of frequency factor A and activation energy $\mathrm{E_A}$ are $4\times10^{13}$ s $^{-1}$ …MediumNumerical value
26 Feb 2021, Shift 2 · Q58If the activation energy of a reaction is 80.9 kJ $\mathrm{mol^{-1}}$ , the fraction of molecules at 700 K, having enough energy to react…MediumNumerical value
2 Apr 2017 (offline) · Q39Two reactions $R_1$ and $R_2$ have identical pre-exponential factors. Activation energy of $R_1$ exceeds that of $R_2$ by 10 kJ…EasySingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.