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Saturday, 31 October

JEE Main 2026 · ChemistryNumerical answerNumerical valueMediumMulti-step

JEE Main 6 April 2026, Shift 2, Chemistry Q73

Question 73 of 75 in this shift, Chemistry question 23 of 25, Section B.

500 mL of 0.2 M MnO4−\mathrm{MnO_4^-} solution in basic medium when mixed with 500 mL of 1.5 M KI solution, oxidises iodide ions to liberate molecular iodine. This liberated iodine is then titrated with a standard xx M thiosulphate solution in presence of starch till the end point. If 300 mL of thiosulphate was consumed, then the value of xx is __________.

Official answer

1

NTA final key.

Same idea in other shifts

Asked 2× in all
  1. 26 Jul 2022, Shift 2 · Q8520 mL of 0.02 M hypo solution is used for the titration of 10 mL of copper sulphate solution, in the presence of excess of KI using starch…MediumNumerical value

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.