JEE Main 2026 · PhysicsMultiple choiceSingle correctEasyCalculation

JEE Main 6 April 2026, Shift 2, Physics Q37

Question 37 of 75 in this shift, Physics question 12 of 25, Section A.

The electric potential as a function of

x, y

is given by

V=5(x^2-y^2)

V. The electric field at a point (2, 3) m is __________ V/m.

(1) $\left(-20\hat{i}+30\hat{j}\right)$ Official answer
(2) $\left(20\hat{i}-30\hat{j}\right)$
(3) $\left(20\hat{i}+45\hat{j}\right)$
(4) $\left(-4\hat{i}+6\hat{j}\right)$

Official answer

Option 1

NTA final key.

Chapter: Electrostatic Potential and Capacitance
Topic: Electric Potential
Idea tested: Field-Potential Relation

Same idea in other shifts

Asked 3× in all

3 Aug 2021, Shift 2 · Q29The electric potential at point $(x, 0, 0)$ is $V = \left(\frac{1000}{x}+\frac{1500}{x^2}+\frac{500}{x^3}\right)$ volt. The electric field…EasyNumerical value
4 Aug 2021, Shift 2 · Q9The electric potential at any point P(x, y, z) is $V=x^3z-x^2y-3$ volts. The electric field $\vec{E}_Q$ at point Q(2, 3, 1) will be (in…EasySingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.