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Saturday, 31 October

JEE Main 2026 · ChemistryNumerical answerNumerical valueMediumMulti-step

JEE Main 5 April 2026, Shift 1, Chemistry Q73

Question 73 of 75 in this shift, Chemistry question 23 of 25, Section B.

One mole of phenol is treated with dilute HNO3\mathrm{HNO_3} at 298 K to give a mixture of products. The mixture is separated by steam distillation. The steam volatile compound (X) is separated. The increase in percentage of oxygen in (X) with respect to phenol is ________ ×10−1\times 10^{-1} % (Given molar mass in g mol−1^{-1} H:1, C:12, N:14, O:16)

Official answer

175

NTA final key.

Same idea in other shifts

Asked 2× in all
  1. 26 Feb 2021, Shift 1 · Q46Given below are two statements : Statement I : oo-Nitrophenol is steam volatile due to intramolecular hydrogen bonding. Statement II :…EasyTwo statements

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.