JEE Main 2026 · PhysicsMultiple choiceSingle correctEasyCalculation

JEE Main 5 April 2026, Shift 1, Physics Q41

Question 41 of 75 in this shift, Physics question 16 of 25, Section A.

Light source having wavelength 331 nm is used to generate photo-electrons whose stopping potential is 0.2 V. The work function of the used metal in the experiment is

\alpha \times 10^{-19}

J. The value of

\alpha

is ______. (

h = 6.62 \times 10^{-34}

J s,

e = 1.6 \times 10^{-19}

C and

c = 3 \times 10^8

m/s)

(1)3.68
(2)4.68
(3)5.68Official answer
(4)2.68

Official answer

Option 3

NTA final key.

Chapter: Dual Nature of Radiation and Matter
Topic: Photoelectric Effect
Idea tested: Einstein's Photoelectric Equation

Same idea in other shifts

Asked 14× in all

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28 Jul 2022, Shift 2 · Q17Two streams of photons, possessing energies equal to five and ten times the work function of metal are incident on the metal surface…EasySingle correct
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29 Jun 2022, Shift 2 · Q36The electric field at a point associated with a light wave is given by…MediumSingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.