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Saturday, 31 October

JEE Main 2026 · MathsNumerical answerNumerical valueHardMulti-step

JEE Main 5 April 2026, Shift 1, Maths Q25

Question 25 of 75 in this shift, Maths question 25 of 25, Section B.

Let y=y(x)y = y(x) be the solution of the differential equation xsin⁡(yx)dy=(ysin⁡(yx)−x)dxx\sin\left(\frac{y}{x}\right)dy = \left(y\sin\left(\frac{y}{x}\right) - x\right)dx, y(1)=π2y(1) = \frac{\pi}{2}, and let α=cos⁡(y(e12)e12)\alpha = \cos\left(\frac{y(e^{12})}{e^{12}}\right). Then the number of integral values of pp, for which the equation x2+y2−2px+2py+α+2=0x^2 + y^2 - 2px + 2py + \alpha + 2 = 0 represents a circle of radius r≤6r \leq 6, is ________.

Official answer

Any non -negative Integer

NTA final key.

Same idea in other shifts

Asked 10× in all
  1. 9 Apr 2024, Shift 1 · Q10The solution of the differential equation (x2+y2)dx−5xy dy=0(x^2+y^2)dx-5xy\,dy=0, y(1)=0y(1)=0, is :MediumSingle correct
  2. 10 Apr 2023, Shift 1 · Q10The slope of tangent at any point (x,y)(x,y) on a curve y=y(x)y=y(x) is x2+y22xy\frac{x^2+y^2}{2xy}, x>0x>0. If y(2)=0y(2)=0, then a value of y(8)y(8) isMediumSingle correct
  3. 25 Jul 2022, Shift 2 · Q25Let y=y(x)y=y(x) be the solution of the differential equation dydx=4y3+2yx23xy2+x3, y(1)=1\frac{dy}{dx}=\frac{4y^3+2yx^2}{3xy^2+x^3},\ y(1)=1. If for some…MediumNumerical value
  4. 28 Jul 2022, Shift 1 · Q1Let the solution curve of the differential equation x dy=(x2+y2+y)dx, x>0x\,dy=\left(\sqrt{x^2+y^2}+y\right)dx,\ x>0, intersect the line x=1x=1 at y=0y=0 and…MediumSingle correct
  5. 28 Jun 2022, Shift 1 · Q10Let the solution curve y=y(x)y=y(x) of the differential equation…HardSingle correct
  6. 29 Jun 2022, Shift 1 · Q2Let the solution curve of the differential equation xdydx−y=y2+16x2x\frac{dy}{dx} - y = \sqrt{y^2 + 16x^2}, y(1)=3y(1) = 3 be y=y(x)y = y(x). Then y(2)y(2) is…MediumSingle correct
  7. 18 Mar 2021, Shift 2 · Q86Let y=y(x)y=y(x) be the solution of the differential equation x dy−y dx=(x2−y2) dxx\,dy-y\,dx=\sqrt{(x^2-y^2)}\,dx, x≥1x\ge1, with y(1)=0y(1)=0. If the area bounded…HardNumerical value
  8. 9 Jan 2020, Shift 2 · Q64If dydx=xyx2+y2\frac{dy}{dx}=\frac{xy}{x^2+y^2}; y(1)=1y(1)=1; then a value of xx satisfying y(x)=ey(x)=e is :MediumSingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.