JEE Main 2026 · MathsMultiple choiceSingle correctMediumMulti-step

JEE Main 5 April 2026, Shift 1, Maths Q15

Question 15 of 75 in this shift, Maths question 15 of 25, Section A.

The square of the distance of the point of intersection of the lines

\vec{r} = (\hat{i} + \hat{j} - \hat{k}) + \lambda(a\hat{i} - \hat{j})

a \neq 0

and

\vec{r} = (4\hat{i} - \hat{k}) + \mu(2\hat{i} + a\hat{k})

from the origin is:

(1)5
(2)10
(3)17Official answer
(4)26

Official answer

Option 3

NTA final key.

Chapter: Three Dimensional Geometry
Topic: Lines in 3D
Idea tested: Condition for Intersection of Two Lines

Same idea in other shifts

Asked 3× in all

7 Apr 2025, Shift 1 · Q13Let the line L pass through $(1, 1, 1)$ and intersect the lines $\frac{x-1}{2} = \frac{y+1}{3} = \frac{z-1}{4}$ and…MediumSingle correct
3 Sep 2020, Shift 1 · Q66The lines $\vec{r}=(\hat{i}-\hat{j})+l(2\hat{i}+\hat{k})$ and $\vec{r}=(2\hat{i}-\hat{j})+\mathrm{m}(\hat{i}+\hat{j}-\hat{k})$ EasySingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.