JEE Main 2026 · MathsMultiple choiceSingle correctMediumMulti-step

JEE Main 5 April 2026, Shift 1, Maths Q10

Question 10 of 75 in this shift, Maths question 10 of 25, Section A.

Let P be a moving point on the circle

x^2 + y^2 - 6x - 8y + 21 = 0

. Then, the maximum distance of P from the vertex of the parabola

x^2 + 6x + y + 13 = 0

is equal to:

(1)8
(2)10
(3)12Official answer
(4)9

Official answer

Option 3

NTA final key.

Chapter: Conic Sections
Topic: General Conic Section
Idea tested: Vertex of Parabola from General Equation

Same topic in other shifts

All General Conic Section questions

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Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.