JEE Main 2026 · PhysicsNumerical answerNumerical valueMediumApplication

JEE Main 2 April 2026, Shift 1, Physics Q49

Question 49 of 75 in this shift, Physics question 24 of 25, Section B.

A uniform wire of length

l

of weight

w

is suspended from the roof with a weight of

W

at the other end. The stress in the wire at

\frac{l}{3}

distance from the top is

\left(\frac{W}{A}+\frac{2}{\gamma}\frac{w}{A}\right)

, where,

A

is the cross sectional area of the wire. The value of

\gamma

is __________.

Official answer

NTA final key.

Chapter: Mechanical Properties of Solids
Topic: Elasticity
Idea tested: Elongation Due to Self-Weight

Same idea in other shifts

Asked 4× in all

26 Jul 2022, Shift 2 · Q55A uniform heavy rod of mass 20 kg, cross sectional area $0.4\ m^2$ and length 20 m is hanging from a fixed support. Neglecting the lateral…MediumNumerical value
26 Jun 2022, Shift 1 · Q54The elongation of a wire on the surface of the earth is $10^{-4}$ m. The same wire of same dimensions is elongated by $6\times10^{-5}$ m…EasyNumerical value
31 Aug 2021, Shift 1 · Q16A uniform heavy rod of weight 10 kg ms $^{-2}$ , cross-sectional area 100 cm $^2$ and length 20 cm is hanging from a fixed support. Young…MediumSingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.