JEE Main 2026 · MathsMultiple choiceSingle correctHardMulti-step

JEE Main 2 April 2026, Shift 1, Maths Q18

Question 18 of 75 in this shift, Maths question 18 of 25, Section A.

The number of critical points of the function

f(x)=\begin{cases}\left|\frac{\sin x}{x}\right|, & x\neq0\\ 1, & x=0\end{cases}

in the interval

(-2\pi, 2\pi)

is equal to :

(1) $1$
(2) $3$
(3) $5$ Official answer
(4) $7$

Official answer

Option 3

NTA final key.

Chapter: Application of Derivatives
Topic: Maxima and Minima
Idea tested: Critical vs Stationary Points

Same idea in other shifts

Asked 3× in all

9 Apr 2024, Shift 2 · Q25Let the set of all values of $p$ , for which $f(x)=(p^2-6p+8)\left(\sin^2 2x-\cos^2 2x\right)+2(2-p)x+7$ does not have any critical point,…MediumNumerical value
25 Feb 2021, Shift 1 · Q87Let $f(x)$ be a polynomial of degree 6 in $x$ , in which the coefficient of $x^6$ is unity and it has extrema at $x = -1$ and $x = 1$ . If…HardNumerical value

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.