JEE Main 2025 · MathsMultiple choiceSingle correctEasyApplication

JEE Main 8 April 2025, Shift 2, Maths Q7

Question 7 of 75 in this shift, Maths question 7 of 25, Section A.

There are 12 points in a plane, no three of which are in the same straight line, except 5 points which are collinear. Then the total number of triangles that can be formed with the vertices at any three of these 12 points is

(1)210Official answer
(2)220
(3)200
(4)230

Official answer

Option 1

NTA final key.

Chapter: Permutations and Combinations
Topic: Permutations and Combinations
Idea tested: Triangles from Points with Collinearity

Same idea in other shifts

Asked 4× in all

3 Apr 2025, Shift 2 · Q7Line $\mathrm{L_1}$ of slope 2 and line $\mathrm{L_2}$ of slope $\frac{1}{2}$ intersect at the origin O. In the first quadrant,…EasySingle correct
4 Apr 2024, Shift 1 · Q7There are 5 points $P_1, P_2, P_3, P_4, P_5$ on the side AB, excluding A and B, of a triangle ABC. Similarly there are 6 points…MediumSingle correct
17 Mar 2021, Shift 2 · Q72If the sides AB, BC and CA of a triangle ABC have 3, 5 and 6 interior points respectively, then the total number of triangles that can be…EasySingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.