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Saturday, 31 October

JEE Main 2025 · ChemistryMultiple choiceSingle correctMediumApplication

JEE Main 8 April 2025, Shift 2, Chemistry Q68

Question 68 of 75 in this shift, Chemistry question 18 of 25, Section A.

When [structure: CH3C(=O)CH2CH2CH2CH2CHO\mathrm{CH_3C(=O)CH_2CH_2CH_2CH_2CHO}, a skeletal zigzag chain with a methyl ketone at one end and an aldehyde (C=O with H) at the other] undergoes intramolecular aldol condensation, the major product formed is :

The figure, in words

Stem shows the skeletal formula of a keto-aldehyde: CH3-C(=O)-(CH2)4-CHO.
  1. (1)[figure: cyclohept-2-en-1-one, seven-membered ring with C=O and an adjacent C=C]
  2. (2)[figure: 2-methylcyclopent-2-en-1-one, five-membered ring with C=O, adjacent ring C=C, methyl on the alkene carbon next to C=O]
  3. (3)[figure: 1-acetylcyclopentene, five-membered ring with ring C=C and an acetyl group on the alkene carbon]Official answer
  4. (4)[figure: 2-methylcyclopent-1-ene-1-carbaldehyde, five-membered ring with C=C, CHO on one alkene carbon and methyl on the other]

Official answer

Option 3

NTA final key.