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Saturday, 31 October

JEE Main 2025 · PhysicsMultiple choiceDiagram basedHardMulti-step

JEE Main 8 April 2025, Shift 2, Physics Q39

Question 39 of 75 in this shift, Physics question 14 of 25, Section A.

Figure shows a current carrying square loop ABCD of edge length is 'a' lying in a plane. If the resistance of the ABC part is r and that of ADC part is 2r, then the magnitude of the resultant magnetic field at centre of the square loop is

The figure, in words

Square loop ABCD drawn as a diamond: current I enters at A (left) and leaves at C (right); upper path A-B-C carries current i1i_1, lower path A-D-C carries i2i_2; side length a marked on BC; centre of the square marked with a dot.
  1. (1)2μ0I3πa\frac{\sqrt{2}\mu_0 I}{3\pi a}Official answer
  2. (2)3πμ0I2a\frac{3\pi\mu_0 I}{\sqrt{2}a}
  3. (3)μ0I2πa\frac{\mu_0 I}{2\pi a}
  4. (4)2μ0I3πa\frac{2\mu_0 I}{3\pi a}

Official answer

Option 1

NTA final key.