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Saturday, 31 October

JEE Main 2025 · PhysicsMultiple choiceSingle correctMediumCalculation

JEE Main 8 April 2025, Shift 2, Physics Q31

Question 31 of 75 in this shift, Physics question 6 of 25, Section A.

A 3 m long wire of radius 3 mm shows an extension of 0.1 mm when loaded vertically by a mass of 50 kg in an experiment to determine Young's modulus. The value of Young's modulus of the wire as per this experiment is P×1011 Nm−2P \times 10^{11}\ \mathrm{Nm^{-2}}, where the value of P is: (Take g=3π m/s2g = 3\pi\ \mathrm{m/s^2})
  1. (1)5Official answer
  2. (2)10
  3. (3)2.5
  4. (4)25

Official answer

Option 1

NTA final key.

Same idea in other shifts

Asked 2× in all
  1. 27 Jul 2022, Shift 2 · Q51In an experiment to determine the Young's modulus, steel wires of five different lengths (1, 2, 3, 4, and 5 m) but of same cross section…MediumNumerical valueHas a figure

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.