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Saturday, 31 October

JEE Main 2025 · ChemistryMultiple choiceDiagram basedEasyData or graph

JEE Main 4 April 2025, Shift 2, Chemistry Q55

Question 55 of 75 in this shift, Chemistry question 5 of 25, Section A.

Consider the following plots of log of rate constant k (log k) vs 1T\frac{1}{T} for three different reactions. The correct order of activation energies of these reactions is :

The figure, in words

Plot of log k (y-axis) vs 1/T (x-axis) with three straight lines of negative slope: line 1 has a moderate slope, line 2 is nearly vertical (steepest), line 3 is nearly flat (gentlest).
  1. (1)Ea2>Ea1>Ea3\mathrm{Ea_2>Ea_1>Ea_3}Official answer
  2. (2)Ea1>Ea2>Ea3\mathrm{Ea_1>Ea_2>Ea_3}
  3. (3)Ea3>Ea2>Ea1\mathrm{Ea_3>Ea_2>Ea_1}
  4. (4)Ea1>Ea3>Ea2\mathrm{Ea_1>Ea_3>Ea_2}

Official answer

Option 1

NTA final key.

Chapter
Chemical Kinetics
Topic
Arrhenius Equation
Idea tested
Log Base 10 Arrhenius Plot Slope

Same idea in other shifts

Asked 4× in all
  1. 28 Jul 2022, Shift 2 · Q58For a reaction, given below is the graph of ln k vs 1T\frac{1}{T}. The activation energy for the reaction is equal to ______ cal…EasyNumerical valueHas a figure
  2. 25 Feb 2021, Shift 1 · Q56For the reaction, aA+bB→cC+dDa\mathrm{A} + b\mathrm{B} \rightarrow c\mathrm{C} + d\mathrm{D}, the plot of log⁡k\log k vs 1T\frac{1}{\mathrm{T}} is…MediumNumerical valueHas a figure
  3. 8 Jan 2020, Shift 2 · Q27Consider the following plots of rate constant versus 1T\frac{1}{T} for four different reactions. Which of the following orders is correct…MediumDiagram basedHas a figure

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. This question needs a figure we do not reproduce; it is described in words above. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.