Learn

Saturday, 31 October

JEE Main 2025 · PhysicsMultiple choiceSingle correctEasyApplication

JEE Main 3 April 2025, Shift 2, Physics Q28

Question 28 of 75 in this shift, Physics question 3 of 25, Section A.

A particle moves along the xx-axis and has its displacement xx varying with time t according to the equation: x=c0 (t2−2)+c (t−2)2x = c_0\,(t^2 - 2) + c\,(t - 2)^2 where c0c_0 and c are constants of appropriate dimensions. Then, which of the following statements is correct?
  1. (1)the initial velocity of the particle is 4c
  2. (2)the acceleration of the particle is 2c02c_0
  3. (3)the acceleration of the particle is 2c
  4. (4)the acceleration of the particle is 2 (c+c0)2\,(c + c_0)Official answer

Official answer

Option 4

NTA final key.

Chapter
Motion in a Straight Line
Topic
Kinematics in 1D
Idea tested
Calculus in Kinematics

Same idea in other shifts

Asked 9× in all
  1. 6 Apr 2024, Shift 2 · Q57A particle moves in a straight line so that its displacement xx at any time tt is given by x2=1+t2x^2=1+t^2. Its acceleration at any time tt…MediumNumerical value
  2. 1 Feb 2024, Shift 1 · Q51A particle is moving in one dimension (along xx axis) under the action of a variable force. It's initial position was 16 m right of…EasyNumerical value
  3. 15 Apr 2023, Shift 1 · Q38The position of a particle related to time is given by x=(5t2−4t+5) mx = (5t^2 - 4t + 5)\,m. The magnitude of velocity of the particle at t=2st = 2s…EasySingle correct
  4. 29 Jul 2022, Shift 1 · Q33If t=x+4t = \sqrt{x} + 4, then (dxdt)t=4\left(\frac{\mathrm{d}x}{\mathrm{d}t}\right)_{t=4} is :EasySingle correct
  5. 25 Jun 2022, Shift 2 · Q32Two buses PP and QQ start from a point at the same time and move in a straight line and their positions are represented by…EasySingle correct
  6. 3 Aug 2021, Shift 1 · Q2For the one-dimensional motion described by x(t)=t−sin⁡tx(t) = t - \sin t A. v(t)<0v(t) < 0 for all t>0t > 0 B. x(t)>0x(t) > 0 for all t>0t > 0 C. v(t)v(t) lies…MediumOther
  7. 25 Jul 2021, Shift 2 · Q3The instantaneous velocity of a particle moving in a straight line is given as v=αt+βt2v = \alpha t + \beta t^2, where α\alpha and β\beta are…EasySingle correct
  8. 17 Mar 2021, Shift 2 · Q11The velocity of a particle is v=v0+gt+Ft2v=v_0+gt+Ft^2. Its position is x=0x=0 at t=0t=0; then its displacement after time (t=1) is :EasySingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.