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Saturday, 31 October

JEE Main 2025 · MathsMultiple choiceSingle correctMediumMulti-step

JEE Main 3 April 2025, Shift 2, Maths Q17

Question 17 of 75 in this shift, Maths question 17 of 25, Section A.

The shortest distance between the curves y2=8xy^2 = 8x and x2+y2+12y+35=0x^2 + y^2 + 12y + 35 = 0 is:
  1. (1)22−12\sqrt{2} - 1Official answer
  2. (2)23−12\sqrt{3} - 1
  3. (3)32−13\sqrt{2} - 1
  4. (4)2\sqrt{2}

Official answer

Option 1

NTA final key.