JEE Main 2025 (2 Apr, Shift 2) Chemistry Q68: Consider the…

Question

Consider the following reactions. From these reactions which reaction will give carboxylic acid as a major product ?
(A) $\mathrm{R-C{\equiv}N} \xrightarrow[	ext{mild condition}]{	ext{(i) H}^+/\mathrm{H_2O}}$
(B) $\mathrm{R-MgX} \xrightarrow[\mathrm{(ii)\ H_3O^+}]{\mathrm{(i)\ CO_2}}$
(C) $\mathrm{R-C{\equiv}N} \xrightarrow[\mathrm{(ii)\ H_3O^+}]{\mathrm{(i)\ SnCl_2/HCl}}$
(D) $\mathrm{R{\cdot}CH_2{\cdot}OH} \xrightarrow{	ext{PCC}}$
(E) $\mathrm{C_6H_5	ext{-}COCl} \xrightarrow[\mathrm{(ii)\ Br_2\ water}]{\mathrm{(i)\ H_2|Pd-BaSO_4}}$ (benzoyl chloride, benzene ring drawn)
Choose the correct answer from the options given below :

Accepted Answer

Option 3: B and E only

Answer

A, B and E only

Answer

B, C and E only

Answer

B and E only

Answer

A and D only

JEE Main 2 April 2025, Shift 2, Chemistry Q68

Same idea in other shifts