JEE Main 2020 · MathsMultiple choiceSingle correctMediumMulti-step

JEE Main 6 September 2020, Shift 2, Maths Q63

Question 63 of 75 in this shift, Maths question 13 of 25.

y=\left(\frac{2}{\pi}x-1\right)\mathrm{cosec}\,x

is the solution of the differential equation,

\frac{dy}{dx}+p(x)y=\frac{2}{\pi}\mathrm{cosec}\,x

0<x<\frac{\pi}{2}

, then the function

p(x)

is equal to :

(1) $\sec x$
(2) $\mathrm{cosec}\,x$
(3) $\tan x$
(4) $\cot x$ Official answer

Official answer

Option 4

NTA final key (Sep 2020).

Chapter: Differential Equations
Topic: Linear Differential Equations
Idea tested: Standard Linear Form Identification

Same idea in other shifts

Asked 4× in all

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Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.