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Saturday, 31 October

JEE Main 2020 · ChemistryMultiple choiceSingle correctMediumCalculation

JEE Main 5 September 2020, Shift 1, Chemistry Q44

Question 44 of 75 in this shift, Chemistry question 19 of 25.

A flask contains a mixture of compounds A and B. Both compounds decompose by first-order kinetics. The half-lives for A and B are 300 s and 180 s, respectively. If the concentrations of A and B are equal initially, the time required for the concentration of A to be four times that of B (in s) is : (Use ln⁡2=0.693\ln 2 = 0.693)
  1. (1)300
  2. (2)120
  3. (3)900Official answer
  4. (4)180

Official answer

Option 3

NTA final key (Sep 2020).

Same idea in other shifts

Asked 13× in all
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  3. 2 Apr 2025, Shift 2 · Q71For the reaction A→BA \rightarrow B the following graph was obtained. The time required (in seconds) for the concentration of A to reduce…MediumNumerical valueHas a figure
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  6. 3 Aug 2021, Shift 2 · Q57The inactivation process of virus is first order with respect to virus concentration and 2% of the virus was inactivated in the first one…MediumNumerical value
  7. 31 Aug 2021, Shift 1 · Q56For a first order reaction, the ratio of the time for 75% completion of a reaction to the time for 50% completion is __________. (Integer…EasyNumerical value
  8. 24 Feb 2021, Shift 2 · Q57Sucrose hydrolyses in acid solution into glucose and fructose following first order rate law with a half-life of 3.33 h at 25∘25^\circC.…MediumNumerical value

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.