JEE Main 2020 · ChemistryMultiple choiceDiagram basedHardMulti-step
JEE Main 5 September 2020, Shift 1, Chemistry Q28
Question 28 of 75 in this shift, Chemistry question 3 of 25.
In the following reaction sequence the major products A and B are :
The figure, in words
Reaction scheme drawn: a six-membered ring with alternating double bonds and two unlabelled line stubs on adjacent ring positions, plus a five-membered ring containing one O atom and two C=O groups (O= drawn above and below the ring), with arrow labelled 'anhydrous AlCl3' giving A, then arrow labelled '1. Zn-Hg/HCl, 2. H3PO4' giving B. Each option is a drawn pair 'A = ... ; B = ...' as summarised in the option text.- (1)[structure] A = a six-membered ring with alternating double bonds and two unlabelled line stubs on adjacent ring positions next to the ring carbon bearing the side chain, bonded to C(=O), then a zig-zag of two more vertices ending in COH; B = a fused two-ring structure (the same six-membered ring with two unlabelled line stubs, fused to a second six-membered ring that has one C=C double bond drawn and a C=O)
- (2)[structure] A = a six-membered ring with alternating double bonds and two unlabelled line stubs on adjacent ring positions away from the ring carbon bearing the side chain, bonded to C(=O), then a zig-zag of two more vertices ending in COH; B = a fused two-ring structure (the same six-membered ring with two unlabelled line stubs, fused to a second six-membered ring with only single bonds drawn and no C=O)
- (3)[structure] A = a six-membered ring with alternating double bonds and two unlabelled line stubs on adjacent ring positions next to the ring carbon bearing the side chain, bonded to C(=O), then a zig-zag of two more vertices ending in COH; B = a fused two-ring structure (the same six-membered ring with two unlabelled line stubs, fused to a second six-membered ring with only single bonds drawn and a C=O)
- (4)[structure] A = a six-membered ring with alternating double bonds and two unlabelled line stubs on adjacent ring positions away from the ring carbon bearing the side chain, bonded to C(=O), then a zig-zag of two more vertices ending in COH; B = a fused two-ring structure (the same six-membered ring with two unlabelled line stubs, fused to a second six-membered ring with only single bonds drawn and a C=O)Official answer
Official answer
Option 4
NTA final key (Sep 2020).
- Chapter
- Hydrocarbons
- Idea tested
- Intramolecular Friedel-Crafts