JEE Main 2020 · PhysicsNumerical answerNumerical valueEasyCalculation

JEE Main 5 September 2020, Shift 1, Physics Q22

Question 22 of 75 in this shift, Physics question 22 of 25.

A force

\vec{F} = (\hat{i} + 2\hat{j} + 3\hat{k})

N acts at a point

(4\hat{i} + 3\hat{j} - \hat{k})

m. Then the magnitude of torque about the point

(\hat{i} + 2\hat{j} + \hat{k})

m will be

\sqrt{x}

N-m. The value of

x

is __________.

Official answer

195.00

NTA final key (Sep 2020).

Chapter: System of Particles and Rotational Motion
Topic: Torque and Equilibrium
Idea tested: Torque Calculation

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Asked 7× in all

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Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.