JEE Main 2020 · PhysicsMultiple choiceSingle correctEasyCalculation

JEE Main 5 September 2020, Shift 1, Physics Q1

Question 1 of 75 in this shift, Physics question 1 of 25.

A physical quantity

z

depends on four observables a, b, c and d, as

z = \frac{a^2 b^{\frac{2}{3}}}{\sqrt{c}\, d^3}

. The percentages of error in the measurement of a, b, c and d are 2%, 1.5%, 4% and 2.5% respectively. The percentage of error in

z

is :

(1)12.25%
(2)14.5%Official answer
(3)13.5%
(4)16.5%

Official answer

Option 2

NTA final key (Sep 2020).

Chapter: Units and Measurements
Topic: Ohm's Law and Resistance
Idea tested: Error Analysis in Ohm's Law

Same idea in other shifts

Asked 7× in all

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25 Jul 2022, Shift 2 · Q49The maximum error in the measurement of resistance, current and time for which current flows in an electrical circuit are 1%, 2% and 3%…EasySingle correct
25 Jun 2022, Shift 2 · Q51For $z =a^2x^3y^{\frac{1}{2}}$ , where ‘ $a$ ’ is a constant. If percentage error in measurement of ‘ $x$ ’ and ‘ $y$ ’ are 4% and 12%,…EasyNumerical value
27 Jun 2022, Shift 1 · Q33A silver wire has a mass $(0.6\pm0.006)$ g, radius $(0.5\pm0.005)$ mm and length $(4\pm0.04)$ cm. The maximum percentage error in the…EasySingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.