Learn

Saturday, 31 October

JEE Main 2020 · MathsMultiple choiceSingle correctMediumMulti-step

JEE Main 4 September 2020, Shift 2, Maths Q55

Question 55 of 75 in this shift, Maths question 5 of 25.

Suppose the vectors x1x_1, x2x_2 and x3x_3 are the solutions of the system of linear equations, Ax=bAx=b when the vector b on the right side is equal to b1b_1, b2b_2 and b3b_3 respectively. If x1=[111]x_1 = \begin{bmatrix}1\\1\\1\end{bmatrix}, x2=[021]x_2 = \begin{bmatrix}0\\2\\1\end{bmatrix}, x3=[001]x_3 = \begin{bmatrix}0\\0\\1\end{bmatrix}, b1=[100]b_1 = \begin{bmatrix}1\\0\\0\end{bmatrix}, b2=[020]b_2 = \begin{bmatrix}0\\2\\0\end{bmatrix} and b3=[002]b_3 = \begin{bmatrix}0\\0\\2\end{bmatrix}, then the determinant of A is equal to :
  1. (1)12\frac{1}{2}
  2. (2)22Official answer
  3. (3)32\frac{3}{2}
  4. (4)44

Official answer

Option 2

NTA final key (Sep 2020).