JEE Main 2020 · MathsMultiple choiceSingle correctMediumMulti-step

JEE Main 4 September 2020, Shift 2, Maths Q52

Question 52 of 75 in this shift, Maths question 2 of 25.

Let

\lambda \neq 0

be in

\mathbf{R}

. If

\alpha

and

\beta

are the roots of the equation,

x^2 - x + 2\lambda = 0

and

\alpha

and

\gamma

are the roots of the equation,

3x^2 - 10x + 27\lambda = 0

, then

\frac{\beta\gamma}{\lambda}

is equal to :

(1) $36$
(2) $27$
(3) $18$ Official answer
(4) $9$

Official answer

Option 3

NTA final key (Sep 2020).

Chapter: Complex Numbers and Quadratic Equations
Topic: Quadratic Roots
Idea tested: Root-Coefficient Relation

Same idea in other shifts

Asked 15× in all

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Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.