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Saturday, 31 October

JEE Main 2020 · ChemistryMultiple choiceDiagram basedHardMulti-step

JEE Main 4 September 2020, Shift 2, Chemistry Q45

Question 45 of 75 in this shift, Chemistry question 20 of 25.

The major product [C] of the following reaction sequence will be : CH2=CH−CHO→(ii) SOCl2(i) NaBH4\mathrm{CH_2=CH-CHO} \xrightarrow[\text{(ii) } \mathrm{SOCl_2}]{\text{(i) } \mathrm{NaBH_4}} [A] →Anhy. AlCl3[ring: hexagon with a circle inside]\xrightarrow[\mathrm{Anhy.\ AlCl_3}]{[\text{ring: hexagon with a circle inside}]} [B] →DBr\xrightarrow{\mathrm{DBr}} [C]

The figure, in words

Stem: reaction scheme with a ring drawn (hexagon with circle inside) above the second arrow; Anhy. AlCl3 below it. Options are drawn line structures.
  1. (1)[figure: ring (hexagon with a circle inside) bonded to a chain of three vertices; the second vertex carries D (drawn downward), the third vertex is bonded to Br]
  2. (2)[figure: ring (hexagon with a circle inside) bonded to a chain of three vertices; the second vertex carries Br (drawn downward), the third vertex is bonded to D]
  3. (3)[figure: ring (hexagon with a circle inside) bonded to a first vertex carrying Br (drawn upward); chain continues through two more vertices, the last bonded to D]Official answer
  4. (4)[figure: ring (hexagon with a circle inside) bonded to a first vertex carrying Br (drawn upward); the second vertex carries D (drawn downward); the chain ends at a third unlabelled vertex]

Official answer

Option 3

NTA final key (Sep 2020).