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Saturday, 31 October

JEE Main 2020 · ChemistryMultiple choiceOtherMediumMulti-step

JEE Main 4 September 2020, Shift 2, Chemistry Q41

Question 41 of 75 in this shift, Chemistry question 16 of 25.

The major product [B] in the following reactions is : CH3−CH2−CH∣CH3−CH2−OCH2−CH3→HeatHI[A] alcohol→ΔH2SO4[B]\mathrm{CH_3-CH_2-\underset{\underset{CH_3}{|}}{CH}-CH_2-OCH_2-CH_3 \xrightarrow[Heat]{HI} [A]\ alcohol \xrightarrow[\Delta]{H_2SO_4} [B]}

The figure, in words

Reaction scheme printed as condensed formulas: CH3-CH2-CH(CH3)-CH2-OCH2-CH3 (CH3 branch drawn above CH) with reagent HI, Heat giving [A] alcohol, then H2SO4, Delta giving [B]. CH3 branch drawn above the carbon in options 1 and 4.
  1. (1)CH3−CH=C∣CH3−CH3\mathrm{CH_3-CH=\underset{\underset{CH_3}{|}}{C}-CH_3}Official answer
  2. (2)CH2=CH2\mathrm{CH_2=CH_2}
  3. (3)CH3−CH2−CH=CH−CH3\mathrm{CH_3-CH_2-CH=CH-CH_3}
  4. (4)CH3−CH2−C∣CH3=CH2\mathrm{CH_3-CH_2-\underset{\underset{CH_3}{|}}{C}=CH_2}

Official answer

Option 1

NTA final key (Sep 2020).

Topic
Ethers